正则表达式从字符串PHP中删除year

Question

I have created a database of cigarette and trading cards. Each set title has a year associated with it. For example, 1943 or 2011 . The year is always 4 characters long, but can be anywhere in the string.

Could someone please help me create a regex that will find the year in the string. I tried '/d{4}\\b/' but it is failing.

Answer 1

(19|20)[0-9][0-9]

这将仅在1900年和2000年的范围内显示。

Answer 2

Try this one :

/\b\d{4}\b/

it will match 4 digits embeded with non-words

Answer 3

Here is a full solution:

$stringWithYear = '1990 New York Marathon';
$stringNoYear = preg_replace('/(19|20)[0-9][0-9]/', '', $stringWithYear);
echo trim($stringNoYear);  // outputs 'New York Marathon'

Answer 4

d{4}\\b will match four d 's at a word boundary. You forgot the backslash in the character class: should be \\d{4}\\b . Depending on the input data you may also want to consider adding another word boundary ( \\b ) at the beginning.

Answer 5

This too works.. preg_match("/^1[0-9]{3}$/",$value))

Checks year of only starting with 1. You could change according to your requirement..