使用Firebug给出javascript命令

Question

I have a page with a list of items and a pagination link:

<a class="paginationNext" href="JavaScript:updFormSubmit('OffSet=2','ZSearchForm')" style="">NEXT</a>

I need to jump to page 50 (offset=50), however by clicking on the link I can only advance page by page.

Is there any way I can use firebug's console to 'simulate' a click on

<a class="paginationNext" href="JavaScript:updFormSubmit('OffSet=50','ZSearchForm')" style="">NEXT</a>

Answer 1

I think you should try the selenium Add-on for Firefox. It allows you to record, edit, and debug tests automatically. Selenium can simulate all kind of user interaction.

Answer 2

You can just execute the updFormSubmit('OffSet=50','ZSearchForm') in the console. ( and click the run button if you have multiline mode on )