使用javascript，如何得到一个元素的position

Question

like the title says, how to get the element's x, y positions with respect to their location in the web page and their positioning schemes like absolute, relative etc.

Answer 1

In a modern browser, getBoundingClientRect and getClientRects will give you rect objects describing your element. See https://developer.mozilla.org/en/DOM/element.getBoundingClientRect and https://developer.mozilla.org/en/DOM/element.getClientRects

If you have to work with IE8, then you'll have to do different things in different browsers to get correct answers (eg object-detect getBoundingClientRect and fall back on some other method if it's not present).

The jQuery offset() calculation and the Quirksmode findPos will give incorrect answers in any browser that does subpixel positioning (eg Firefox or IE9), because they will round the answer to an integer number of pixels. Depending on what you're doing, that may or may not be ok.

Answer 2

With jQuery:

var $elt = $('select an element however'),
    cssPosition = $elt.css('position'),
    offset = $elt.offset(),
    top = offset.top,
    left = offset.left;

Without jQuery, use Quirksmode's findPos function :

var elt = document.getElementBy...,
    pos = findPos(elt),
    top = pos[1],
    left = pos[0];

Getting the computed CSS position value without a library is another can of worms . It boils down to:

• element.currentStyle (IE)
• getComputedStyle(element) (real browsers)

Answer 3

Check out this

JS:

function findPos(obj) {
    var curleft = curtop = 0;
    if (obj.offsetParent) {
        curleft = obj.offsetLeft
        curtop = obj.offsetTop
        while (obj = obj.offsetParent) {
            curleft += obj.offsetLeft
            curtop += obj.offsetTop
        }
    }
    return [curleft,curtop];
}

HTML:

<div id="ser">&nbsp;TEST</div>

RETURN CALL:

alert(findPos(document.getElementById('ser')));

I hope its help to you