从 SurfaceView 内部启动活动

Question

I'm trying to start an Activity (StartGame) from inside of a SurfaceView once I touch in a certain spot. This code is inside the OnTouchEvent

It won't accept what I have below, of course, but I don't know what to put in the Context space.

I've tried my package (com.Juggle2.Menu), but that doesn't work, because it can't resolve it to a variable, and "this" doesn't work because it's a class. I don't know what else to try.

startActivity(new Intent(com.Juggle2.Menu, StartGame.class));

This does not work because "com.Juggle2.Menu cannot be resolved to a variable"

My Manifest is as follows

<application android:icon="@drawable/icon" android:label="@string/app_name">
    <activity android:name=".Juggle2"
              android:label="@string/app_name">
        <intent-filter>
            <action android:name="android.intent.action.MAIN" />
            <category android:name="android.intent.category.LAUNCHER" />
        </intent-filter>
    </activity>
    <activity android:name=".Menu"
              android:label="@string/app_name">
        <intent-filter>
            <action android:name="android.intent.action.MAIN" />
            <category android:name="android.intent.category.LAUNCHER" />
        </intent-filter>
    </activity>

  <activity android:name=".StartGame">
    </activity>
        <activity android:name = ".Help">
        </activity>
        <activity android:name = ".Options">
        </activity>
        <activity android:name = ".Credits">
        </activity>
</application>

And my project goes com.Juggle2>Menu.java

Answer 1

Try startActivity(new Intent(com.Juggle2.Menu.this, StartGame.class));

Edit working:

Context context = com.Juggle2.Menu.this.getContext();
context.startActivity(new Intent(context, StartGame.class));