[英]Having trouble using Structures and Pointers in C
I am programming in C.我正在 C 中编程。 Considering the following Code.
考虑以下代码。
My structure is defined as:我的结构定义为:
// Define the stack
struct stackNode {
char data;
struct stackNode *nextPtr;
};
typedef struct stackNode StackNode;
typedef StackNode *StackNodePtr;
The following Variables are used:使用以下变量:
StackNode topTracker; // The pointer of this stackNode will always point to the top of the stack
And I am trying to complete the following function.我正在尝试完成以下 function。
char pop( StackNodePtr *topPtr ){
char returnable;
// store the Node.data from the top of the stack
returnable = *topPtr.data; //[1]
// Set the next Node to the top of the stack
topTracker.nextPtr = *topPtr.nextPtr; //[2]
// return the Node data.
return returnable;
The problem is I get the following error: at Point [1] & [2] respectively问题是我收到以下错误:分别在点 [1] 和 [2]
"request for member data' in something not a structure or union" "request for member
nextPtr' in something not a structure or union" “在非结构或联合的事物中请求成员
data' in something not a structure or union" "request for member
nextPtr”
How do I get around this error and actually access the data and nextPtr of the pointer *topPtr?如何解决此错误并实际访问指针 *topPtr 的数据和 nextPtr? Given that *topPtr will be a pointer to an actual StackNode at runtime.
鉴于 *topPtr 在运行时将是一个指向实际 StackNode 的指针。
topPtr
is of type StackNodePtr*
which is an alias for StackNode**
. topPtr
是StackNodePtr*
类型,它是StackNode**
的别名。 This means that *topPtr
is of type StackNode*
which is a pointer type and you must access the members using ->
.这意味着
*topPtr
是StackNode*
类型,它是一个指针类型,您必须使用->
访问成员。
Also beware that the operators .
还要提防经营者
.
and ->
bind stronger than unary *
.和
->
绑定比一元*
更强。 You therefore have to use parenthesis to manipulate the evaluation order:因此,您必须使用括号来操纵评估顺序:
returnable = (*topPtr)->data;
or或者
returnable = (**topPtr).data;
*topPtr
gives a StackNodePtr
. *topPtr
给出一个StackNodePtr
。 which is still one level away from the structure.离结构还有一层。 you need to dereference it once again to get StackNode.
您需要再次取消引用它以获取 StackNode。
(**topPtr)
will give the StackNode. (**topPtr)
将给出 StackNode。
use (**topPtr).data
or (*Ptr)->data
to get to the structure member.使用
(**topPtr).data
或(*Ptr)->data
获取结构成员。
u r using wrong syntax it shud be topPtr->data. u r 使用了错误的语法,它应该是 topPtr->data。 Also if u need to learn, learn now about memory leaks.
此外,如果您需要学习,请立即了解 memory 泄漏。 It is there in ur above program.
它在你上面的程序中。 so as soon as u retrieve ur data free the memory Eg.
所以一旦你检索到你的数据,memory 例如。 returnable = topPtr->data;
可返回 = topPtr-> 数据; StackNodePtr *tmp = topPtr;
StackNodePtr *tmp = topPtr; topTracker->nextPtr = topPtr->nextPtr;
topTracker->nextPtr = topPtr->nextPtr; free(tmp);
免费(tmp); return returnable;
可退货;
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