在 Javascript function 中返回与回调

Question

Say I write this function...

var sayHi = function() {
  return "hi";
}

alert(sayHi()); will return "hi".

Now if I write it this way...

var sayHi = function(callback) {
  callback("hi");
}

How do I display "hi" with this function?

Based on an example here: http://nowjs.com/doc

Answer 1

You pass a function to sayHi, so I imagine this:

sayHi(alert);

Answer 2

you must have defined some callback function or pass a anonymous function:

var sayHi = function(callback) {
  callback("hi");
}

sayHi(function(message){
  alert(message);
});

Answer 3

sayHi(function(value) {
    alert(value);
});

Answer 4

Try this:

sayHi(function(msg){
    alert(msg)
});

Your new sayHi function doesn't return a value, so you have to perform the alert in the callback function.

Answer 5

sayHi(function(msg) {
    alert(msg);
});

You have to invert your thinking process when using callbacks. Instead of writing the next operation first, you write the next operation last.

Answer 6

Here in example callback is a function. So you should pass function argument.

You may do this in 2 ways:

var some_fun = function(some_str) {
    alert(some_str);
}

var sayHi = function(callback) {
  callback("hi");
}

    sayHi(some_fun)

or you can pass function when you call it:

var sayHi = function(callback) {
  callback("hi");
}

sayHi(function(some_str){
  alert(some_str);
});