创建 WPF 弹出窗口

Question

I want to create a modal popup. So far I have made a window which I create when I need it. But I don't think that is the right way to do this. The problem is, everytime I call it, it opens about 20px to the right and 20px lower than previous one. It's annoying. Is this default behaviour or am I doing something wrong here?

Success win1 = new Success();
win1.ShowDialog();

Also, I want it to be centered if that's possible?

Answer 1

Below will center the your dialog box to the owner/parent form.

Success win1 = new Success();
win1.Owner = this; // For example , see the parent window here
win1.WindowStartupLocation = WindowStartupLocation.CenterOwner;
win1.ShowDialog();

Below are the alternative if you want to try. If you want to Center it to the screen use 'CenterScreen'

Manual - The startup location of a Window is set from code, or defers to the default Windows location.

CenterScreen - The startup location of a Window is the center of the screen that contains the mouse cursor.

CenterOwner - The startup location of a Window is the center of the Window that owns it, as specified by the Window.Owner property.

Answer 2

You want to set the WindowStartupLocation member of the Success window. Sounds like CenterOwner is the value you want.