PHP - 从查询结果中获取对象数组

Question

Simplified version of the problem:

So I have this query which is inside a function.

$query = "SELECT * FROM users";
$result = mysql_query($query);

How I want to use mysql_fetch_object() to get an object from a row.

Because in the end I wanted to get an array of objects I do this:

while ($a[] = mysql_fetch_object($result)) { // empty here }

In the end the function just returns $a. And it works almost fine.

My problem is that mysql_fetch_object will return at the end a NULL "row" (which is normal because the result ended but I still assigned it to the array).

Any ideas on how to do this in a decent way? Thanks in advance.

Answer 1

Or you could move the assignment from the while condition to the while body like:

<?php
while ($entry = mysql_fetch_object($result)) {
   $a[] = $entry;
}

Answer 2

mysql_fetch_object actually returns FALSE if there are no more rows. I would do this:

$a = array();
while (($row = mysql_fetch_object($result)) !== FALSE) {
  $a[] = $row;
}

Answer 3

This question seems like duplicate of how to fetch all the row of the result in php mysql?

//Database Connection
$sqlConn =  new mysqli($hostname, $username, $password, $database);

//Build SQL String
$sqlString = "SELECT * FROM my_table";

//Execute the query and put data into a result
$result = $this->sqlConn->query($sqlString);

//Copy result into a associative array
$resultArray = $result->fetch_all(MYSQLI_ASSOC);

//Copy result into a numeric array
$resultArray = $result->fetch_all(MYSQLI_NUM);

//Copy result into both a associative and numeric array
$resultArray = $result->fetch_all(MYSQLI_BOTH);

Answer 4

You can just add

array_pop($a);

after the while

http://php.net/manual/en/function.array-pop.php