[英]double.parse returning a precision difference
Why does double.parse ("1833.35")
return value 1833.349999999999
?为什么
double.parse ("1833.35")
返回值1833.349999999999
?
It's because floating-point values are represented in the machine with binary exponents, and 10 is not an even power of 2. Thus, some base-10 fractions turn into repeating fractions when converted.这是因为浮点值在机器中用二进制指数表示,而 10 不是 2 的偶数幂。因此,一些以 10 为底的分数在转换时会变成重复分数。
To illustrate, just work out how you'd represent 35/100 in binary.为了说明,只需计算出如何用二进制表示 35/100。
You could switch to using a decimal instead of a double if you need it to be absolutely correct.如果您需要绝对正确,您可以切换到使用小数而不是双精度。 Decimal stores the number with a base 10 exponent.
Decimal 存储以 10 为底的指数的数字。
There is no way to represent.35 exactly using a double or float.没有办法完全使用双精度或浮点数来表示。35。
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