求助，Javascript正则表达式

Question

I'm always fighting with regular expression, some help would be appreciated.

What is the best way to get all parameters (words starting with @) in strings like:

statement : "SELECT @Measure on 0, TOPCOUNT(@Hierarchy.levels(1).member) where @Measure"

This expression is not working correctly:

var paramsNames = mdxStatement.match(/(^|\s|-)+@(\w+)/g);

The expected result is: @Measure,@Hierarchy

Thanks a lot in advance

Answer 1

Use this:

"SELECT @Measure on 0, TOPCOUNT(@Hierarchy.levels(1).member) where @Measure".match(/(@\w+)/g);

And remove the last item, if you do not need it.

:)

Answer 2

In this case you will use

var match = string.match(/(@\w+)/g);

thats it

Answer 3

What about:

var paramsNames = mdxStatement.match(/(@[a-z]+)/gi);

To grab unique params do:

var paramsNames = mdxStatement.match(/(@[a-z]+)/gi).unique();

Answer 4

I believe

/@\b.+?\b/g

should do what you want

Array.prototype.unique = function() {
    var o = {}, i, l = this.length, r = [];
    for(i=0; i<l;i+=1) o[this[i]] = this[i];
    for(i in o) r.push(o[i]);
    return r;
};

var string = "SELECT @Measure on 0, TOPCOUNT(@Hierarchy.levels(1).member) where @Measure";
var pattern = /@\b.+?\b/g;

var params = string.match(pattern).unique();

demo http://jsfiddle.net/gaby/se7Np/1/