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使用 JPA 时出现“java.lang.NoSuchFieldError”

[英]'java.lang.NoSuchFieldError' while using the JPA

I am getting the following error while trying out this JPA tutorial :尝试此JPA 教程时出现以下错误:

java.lang.NoSuchFieldError: NONE
    at org.hibernate.ejb.QueryImpl.<init>(QueryImpl.java:609)
    at org.hibernate.ejb.QueryImpl.<init>(QueryImpl.java:80)
    at org.hibernate.ejb.AbstractEntityManagerImpl.createQuery(AbstractEntityManagerImpl.java:272)
    at entity.PersonTest.insertAndRetrieve(PersonTest.java:50)
    at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method)
    at sun.reflect.NativeMethodAccessorImpl.invoke(Unknown Source)
    at sun.reflect.DelegatingMethodAccessorImpl.invoke(Unknown Source)
    at java.lang.reflect.Method.invoke(Unknown Source)
    at org.junit.runners.model.FrameworkMethod$1.runReflectiveCall(FrameworkMethod.java:44)
    at org.junit.internal.runners.model.ReflectiveCallable.run(ReflectiveCallable.java:15)
    at org.junit.runners.model.FrameworkMethod.invokeExplosively(FrameworkMethod.java:41)
    at org.junit.internal.runners.statements.InvokeMethod.evaluate(InvokeMethod.java:20)
    at org.junit.internal.runners.statements.RunBefores.evaluate(RunBefores.java:28)
    at org.junit.internal.runners.statements.RunAfters.evaluate(RunAfters.java:31)
    at org.junit.runners.BlockJUnit4ClassRunner.runChild(BlockJUnit4ClassRunner.java:76)
    at org.junit.runners.BlockJUnit4ClassRunner.runChild(BlockJUnit4ClassRunner.java:50)
    at org.junit.runners.ParentRunner$3.run(ParentRunner.java:193)
    at org.junit.runners.ParentRunner$1.schedule(ParentRunner.java:52)
    at org.junit.runners.ParentRunner.runChildren(ParentRunner.java:191)
    at org.junit.runners.ParentRunner.access$000(ParentRunner.java:42)
    at org.junit.runners.ParentRunner$2.evaluate(ParentRunner.java:184)
    at org.junit.runners.ParentRunner.run(ParentRunner.java:236)
    at org.eclipse.jdt.internal.junit4.runner.JUnit4TestReference.run(JUnit4TestReference.java:49)
    at org.eclipse.jdt.internal.junit.runner.TestExecution.run(TestExecution.java:38)
    at org.eclipse.jdt.internal.junit.runner.RemoteTestRunner.runTests(RemoteTestRunner.java:467)
    at org.eclipse.jdt.internal.junit.runner.RemoteTestRunner.runTests(RemoteTestRunner.java:683)
    at org.eclipse.jdt.internal.junit.runner.RemoteTestRunner.run(RemoteTestRunner.java:390)
    at org.eclipse.jdt.internal.junit.runner.RemoteTestRunner.main(RemoteTestRunner.java:197)

Here is my persistence.xml :这是我的坚持。xml

<?xml version="1.0" encoding="UTF-8"?>
<persistence xmlns="http://java.sun.com/xml/ns/persistence"
    xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
    xsi:schemaLocation="http://java.sun.com/xml/ns/persistence http://java.sun.com/xml/ns/persistence/persistence_2_0.xsd"
    version="2.0">

    <persistence-unit name="examplePersistenceUnit" transaction-type="RESOURCE_LOCAL">
        <class>entity.Person</class>
        <properties>
            <property name="hibernate.show_sql" value="false" />
            <property name="hibernate.format_sql" value="false" />

            <property name="hibernate.connection.driver_class" value="com.mysql.jdbc.Driver" />
            <property name="hibernate.connection.url" value="jdbc:mysql://localhost:3306/jpa_test" />
            <property name="hibernate.connection.username" value="root" />
            <property name="hibernate.connection.password" value="admin" />

            <property name="hibernate.dialect" value="org.hibernate.dialect.MySQLDialect" />
            <property name="hibernate.hbm2ddl.auto" value="create" />
        </properties>
    </persistence-unit>
</persistence>

Person.java人.java

   package entity;

    import javax.persistence.Entity;
    import javax.persistence.GeneratedValue;
    import javax.persistence.Id;
    import javax.persistence.Table;

    @Entity 
    public class Person {

        @Id
        @GeneratedValue
        private int id;
        private String firstName;
        private char middleInitial;
        private String lastName;
        private String streetAddress1;
        private String streetAddress2;
        private String city;
        private String state;
        private String zip;

    .
    .
    .
    (getters and setters)

Part of my JUnit Test file:我的 JUnit 测试文件的一部分:

@SuppressWarnings("unchecked")
    @Test
    public void insertAndRetrieve() {
        em.getTransaction().begin();
        em.persist(p1);
        em.persist(p2);
        em.getTransaction().commit();

        final List<Person> list = em.createQuery("select p from Person p")
                .getResultList();
        System.out.println("here...");

        assertEquals(2, list.size());

I am using MySQL db, the 'person' table is present in the database.我正在使用 MySQL 数据库,数据库中存在“人”表。 And after之后

em.getTransaction().begin();
em.persist(p1);
em.persist(p2);
em.getTransaction().commit();

I can see the two records are inserted in the person table.我可以看到这两条记录都插入到了 person 表中。 But on the next statement, it fails.但是在下一个语句中,它失败了。

EDIT 1: JARs in my build path:编辑 1: JARs 在我的构建路径中:

antlr-2.7.6.jar, 
commons-collections-3.1.jar, 
dom4j-1.6.1.jar, hibernate3.jar, 
hibernate-annotations-3.5.5-Final.jar, 
hibernate-commons-annotations-3.2.0.Final.jar, 
hibernate-entitymanager-3.5.5-Final.jar, 
hibernate-entitymanager-3.5.5-Final-sources.jar, 
javaee-api-5.0-3.jar, 
javassist-3.9.0.GA.jar, 
log4j-1.2.12.jar, 
mysql-connector-java-5.1.15.jar, 
slf4j-api-1.6.1.jar, 
slf4j-simple-1.6.1.jar, 
hibernate-jpa-2.0-api-1.0.0-CR-1.jar

Can anyone tell me what I am doing wrong?谁能告诉我我做错了什么?

Thanks.谢谢。

Remove the ejb3-persistence.jar JAR file from the class path.从 class 路径中删除 ejb3-persistence.jar JAR 文件。 It contains the interfaces of the JPA 1.0 specification.它包含 JPA 1.0 规范的接口。 You'll need to retain the hibernate-jpa-2.0-api-1.0.0-CR-1.jar JAR file, for it contains the interfaces for the JPA 2.0 specification.您需要保留 hibernate-jpa-2.0-api-1.0.0-CR-1.jar JAR 文件,因为它包含 Z9CE3D1BD8890F16A0C448Z29059 规范的接口。

Note: If you need to work against JPA 1.0, then do not use Hibernate 3.5.5 for it contains the JPA 2.0 implementation.注意:如果您需要使用 JPA 1.0,请不要使用 Hibernate 3.5.5,因为它包含 JPA 2.0 实现。 In the future, use Maven for dependency management;以后使用Maven进行依赖管理; it will help you avoid these issues.它将帮助您避免这些问题。

Addendum:附录:

If I were to setup Hibernate EntityManager 3.5.5 (JPA 2) from scratch, these would be the files I would consider.如果我要从头开始设置 Hibernate EntityManager 3.5.5 (JPA 2),我会考虑这些文件。 The following list has been inferred from the Hibernate documentation :以下列表是从Hibernate 文档中推断出来的

  • hibernate3.jar hibernate3.jar
  • hibernate-jpa-2.0-api-1.0.0.Final.jar hibernate-jpa-2.0-api-1.0.0.Final.jar
  • antlr-2.7.6.jar antlr-2.7.6.jar
  • commons-collections-3.1.jar commons-collections-3.1.jar
  • dom4j-1.6.1.jar dom4j-1.6.1.jar
  • javassist-3.9.0.GA.jar javassist-3.9.0.GA.jar
  • jta-1.1.jar jta-1.1.jar
  • slf4j-api-1.5.8.jar and either of slf4j-api-1.5.8.jar 和任何一个
    • cglib-2.2.jar, or cglib-2.2.jar,或
    • javassist-3.9.0.GA.jar javassist-3.9.0.GA.jar

The last two haven't been mentioned in the documentation, but are required.最后两个在文档中没有提到,但是是必需的。 I don't see the need for any of the other JARs, except for mysql-connector-java-5.1.15.jar and log4j-1.2.12.jar (both of which could be retained).我认为不需要任何其他 JARs,除了 mysql-connector-java-5.1.15.jar 和 log4j-1.2.12.Z68995FCBF432492D15Z484 的 mysql-connector-java-5.1.15.jar 和 log4j-1.2.12.Z68995FCBF432492D15Z484 可以保留)。

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