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Django TypeError: 'RelatedManager' object 不可迭代

[英]Django TypeError: 'RelatedManager' object is not iterable

I have these Django models:我有这些 Django 型号:

class Group(models.Model):
    name = models.CharField(max_length=100)
    parent_group = models.ManyToManyField("self", blank=True)
    
    def __unicode__(self):
        return self.name


class Block(models.Model):
    
    name = models.CharField(max_length=100)
    app = models.CharField(max_length=100)
    group = models.ForeignKey(Group)

    def __unicode__(self):
        return self.name

Lets say that block b1 has the g1 group.假设块b1具有g1组。 By it's name I want to get all blocks from group g1 .按它的名字,我想从组g1中获取所有块 I wrote this recursive function:我写了这个递归 function:

def get_blocks(group):
    
    def get_needed_blocks(group):
        for block in group.block_set:
            blocks.append(block)

        if group.parent_group is not None:
            get_needed_blocks(group.parent_group)

    blocks = []
    get_needed_blocks(group)
    return blocks
    

But b1.group.block_set returns a RelatedManager object, which is not iterable.但是b1.group.block_set返回一个RelatedManager object,它是不可迭代的。

What am I doing wrong and how can I fix it?我做错了什么,我该如何解决?

Try this:尝试这个:

block in group.block_set.all()

Use it like a Manager .Manager一样使用它。 If you want all the objects then call the all() method.如果您想要所有对象,请调用all()方法。

you have to use.all() with related name or childModel_set model name.您必须使用相关名称或 childModel_set model 名称的 use.all()。

in views.py use:在views.py 中使用:

for item in object.relatedname.all():
    do something ......

in html templates use:在 html 模板中使用:

 {% for item in object.relatedname.all %}
   do something ......
 {% endfor %}

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