如何获取 Haskell 列表中的元组数

Question

i want to get the sum of tupples in a list. for an example

[("Isuru1","Ranasinghe1",123),("Isuru2","Ranasinghe2",123),("Isuru3","Ranasinghe3",123),("Isuru4","Ranasinghe4",123)]

in above list the answer has to be 4. please help me to solve this. i am new to haskell:(

Answer 1

Use the length function. It gets the length of any list, no matter what's in it.

Example:

Prelude> length [("Isuru1","Ranasinghe1",123),("Isuru2","Ranasinghe2",123),("Isuru3","Ranasinghe3",123),("Isuru4","Ranasinghe4",123)]
4