[英]Use of variable '$name' in a function
I like to think I'm quite knowledgeable on php, but this has baffled me.我喜欢认为我对 php 非常了解,但这让我感到困惑。
Keeping it basic I have:保持基本我有:
function req_new($pname, $use=null, $depID=null, $manID=null, $manName=null, $suppID=null, $suppName=null, $cat=null, $brand=null, $name, $email, $custom_code, $user=null, $method=null)
{
//validation
if($pname == ''){return false;}
if($manID==null AND $manName==null){return false;}
foreach(func_get_args() as $arg)
{
$arg = fquery_sanitize($arg);
}
//submit new request
$sql = "insert into sds_product_requests ".
"(prodName, produse, depID, reqDate, manID, manName, suppID, suppName, prodCat, prodBrand, Name, Email, InternalC, `user`, method) ".
"VALUES ".
"('$pname','$use','$depID', NOW(),'$manID', '$manName', '$suppID', '$suppName', '$cat', '$brand', '$name', '$email', '$custom_code', '$user', $method)";
$result = fquery_db($sql);
if($result>1)
{return true;}
else
{return false;}
}
If the code uses the variable name $name
, it does not work.如果代码使用变量名
$name
,则它不起作用。 Using another variable name instead, like $pname
, it works.改用另一个变量名,如
$pname
,它可以工作。 If I use the variable name $name
, it returns false.如果我使用变量名
$name
,它会返回 false。
Any ideas as to why this is happening?关于为什么会发生这种情况的任何想法?
Calling the function调用 function
<?php
$name = getPOST('name');
$depID = getPOST('depID');
$cat = getPOST('cat');
$supp = getPOST('supp');
$suppID = getPOST('suppID');
$man = getPOST('man');
$manID = getPOST('manID');
$confirm = req_new('THIS IS A NAME', null, $depID, $manID, $man, $suppID, $supp, $cat, null, null, null, null, fauth_GetUserID(), 1);
?>
I can't reproduce OP's phenomenon, at least not within the extent of the code OP has posted.我无法重现 OP 的现象,至少不能在 OP 发布的代码范围内。
<?php
function bla($name, $whatever, $bla)
{
if ($name == '') { return false; }
return true;
}
$name = "ORLY?";
echo bla($name, null, null) . "\n"; // prints 1, as expected
?>
From comments below the question - there were two arguments named $name
, with second one being set to NULL
:根据问题下方的评论 - 有两个名为
$name
的 arguments ,第二个设置为NULL
:
function req_new(
$pname, /* first $name, wich started to work after renaming to $pname */
$use=null, $depID=null, $manID=null, $manName=null, $suppID=null,
$suppName=null, $cat=null, $brand=null,
$name, /* second $name, which was set to NULL and overrode first argument */
$email, $custom_code, $user=null, $method=null)
{
// ...
}
$name
is not a special variable name, php only reserves names starting with __
(and there are a few inherited predefined variables). $name
不是特殊的变量名,php 只保留以__
开头的名称(并且有一些继承的预定义变量)。 I couldn't find a single program where $name
is handled differently.我找不到一个以不同方式处理
$name
的程序。 Can you provide a complete example?你能提供一个完整的例子吗?
Note that you're missing a semicolon after return false
though.请注意,您在
return false
之后缺少分号。 Turn on error debugging to see these errors.打开错误调试以查看这些错误。
How are you calling the code?你如何调用代码? Since you're doing a regular equality test (
==
), remember that PHP will auto-convert values for you, and there are quite a few values that are equal to an empty string.由于您正在进行常规相等测试 (
==
),请记住 PHP 将为您自动转换值,并且有很多值等于空字符串。
eg例如
bla(0, ...);
will still trigger the return, because in PHP-land 0
is equivalent to ''
in an equality test.仍然会触发返回,因为在 PHP-land
0
中等于''
在相等测试中。 ( 0 == ''
is TRUE). (
0 == ''
为真)。 Use the strict equality test to force checking value AND type:使用严格相等测试来强制检查值和类型:
if ($blah === '') {
return false;
}
This will work as expected, because while 0 == ''
, the strict check invisibly tacks on a an int == string
check, which evaluates to FALSE.这将按预期工作,因为当
0 == ''
时,严格检查无形地附加了一个int == string
检查,其计算结果为 FALSE。
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