[英]Casting a long to an Int returns in '-1'?
Is it safe to cast a long to an int in Java?在 Java 中将 long 转换为 int 是否安全?
For some reason, the following code, I get '-1' as anIntVar.出于某种原因,下面的代码中,我得到'-1' 作为 anIntVar。 And I have checked 'aLongVar' is not an -1.我已经检查过'aLongVar'不是-1。
public static final long CONST = 1000 * 62;
long aLongVar
int anIntVar = (int)(aLongVar/ CONST);
If it was safe it wouldn't require an explicit cast.如果它是安全的,则不需要显式强制转换。
No, its not safe.不,它不安全。 Don't do it.不要这样做。 Because, A Long / long
has 64 bit and can hold much more data than an Integer / int
has 32 bit only.因为,A Long / long
有64 位,并且可以保存比Integer / int
只有32 位更多的数据。 Doing the conversion will result in loss of information.进行转换将导致信息丢失。
If at all you wish to do it, do like this如果您想这样做,请这样做
Use the .intValue()
to convert the Long
value to an int
value.使用.intValue()
将Long
值转换为int
值。
A long
is 64 bits, and an int
is 32 bits, so no, it's not safe. long
是 64 位, int
是 32 位,所以不,它不安全。
Try尝试
int anIntVar = Math.rint(aLongVar);
You can cast a long to an int and get meaningful results if the value in the long will fit in an int.如果 long 中的值适合 int,您可以将 long 转换为 int 并获得有意义的结果。 If not, you will get high bits truncated.如果没有,您将被截断高位。 In your example you don't show what was in the numerator before you did the division, but -1 is certainly not an impossible value given the right inputs.在您的示例中,您没有在进行除法之前显示分子中的内容,但是在正确的输入下,-1 肯定不是不可能的值。
Is it legal?合法吗? Yes.是的。 Is it safe?安全吗? No, not unless you do range checks, or are confident that you know your inputs well enough.不,除非您进行范围检查,或者确信您对输入足够了解。
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