Mysql 语法错误……还是 PHP？

Question

Can someone help me figure out what is wrong with this function?? I am getting a mysql syntax error...

function category_exists($name) {
    $name = mysql_real_escape_string($name);

    $query = mysql_query("SELECT COUNT(1) FROM 'categories' WHERE 'name' = '{$name}'"); 
    return (mysql_result($query, 0) == '0')? false : true;
}

Answer 1

You should not have quotes around your table and column name ( categories , name ). If you need to escape a table or column names, you should use backquotes (`). IE:

$query = mysql_query("SELECT COUNT(1) FROM `categories` WHERE `name` = '{$name}'"); 

Answer 2

function category_exists($name) {
  $name = mysql_real_escape_string($name);

  $query = mysql_query("SELECT COUNT(1) FROM `categories` WHERE `name` = '{$name}'"); 
  return (mysql_result($query, 0) == '0')? false : true;
}

You need either backquotes (`) or NO quotes around table names and field names.

Answer 3

Strings are quoted. Object names (tables, columns...) are not.

Answer 4

Try changing the query to

"SELECT COUNT(*) FROM 'categories' WHERE name = '$name'"