时间戳中的错误日期

Question

I have a problem which can't solve by myself.

Here is timestamp 1308085200 taken from my website database. It represents 2011-06-15 12:00:00

Here is javascript code which I use to "fetch" date in human readable format.

var date    = new Date(1308085200 * 1000);
var year    = date.getFullYear();
var month   = date.getMonth();
var day     = date.getDate();
var hour    = date.getUTCHours();
var minute  = date.getUTCMinutes();
var seconds = date.getUTCSeconds();

The problem is that I get wrong results. For example the code above shows 2011-5-15 21:0:0 instead of 2011-06-15 12:00:00

What I do wrong and how to fix that?

Answer 1

JavaScript's Date::getMonth() returns a zero-based integer from 0 to 11 which is why your date is showing May instead of June.

https://developer.mozilla.org/en/JavaScript/Reference/Global_Objects/Date/getMonth

Update

As for the time portion, this is what I get (AEST)

var d = new Date(1308085200000); // Wed Jun 15 07:00:00 GMT+1000 (EST)
d.toUTCString() // Tue, 14 Jun 2011 21:00:00 GMT
d.getUTCFullYear() // 2011
d.getUTCMonth() // 5
d.getUTCDate() // 14
d.getUTCHours() // 21
d.getUTCMinutes() // 0
d.getUTCSeconds() // 0

Looks like your timestamp is actually not what you think it is.

Answer 2

Well, JavaScript's getMonth() function sucks and starts with 0 for January. You have to add one.

Maybe you want to use date js , since it fixes some of these problems.

Answer 3

The date and time can vary dependent on the timezone you're in. That's why in my zone (GMT+2000) new Date(1308085200*1000) displays Tue Jun 14 2011 23:00:00 GMT+0200 (W. Europe Daylight Time) . Check this reference for everything you always wanted to know about dates in javascript

Regarding formatting (leading zero's etc.), maybe this jsfiddle can help you?

Answer 4

Try this:

 function timeConverter(createdAt) {
  var date = new Date(createdAt);
  date.toUTCString()
  var year = date.getUTCFullYear();
  var month = date.getUTCMonth()+1;
  var day = date.getUTCDate();
  return day+"-"+month+"-"+year;
}