mysql 查询特定日期和时间段内酒店的客房供应情况

Question

I need help to find out a query to check the availability of rooms in a hotel for a particular date and time duration. I am explaining it below.

Table "hotel_room_book" has the folloing columns.

CREATE TABLE IF NOT EXISTS `hotel_room_book` (
  `hotel_room_book_id` int(10) NOT NULL AUTO_INCREMENT,
  `hotel_room_id` int(10) NOT NULL,
  `hotel_id` int(10) NOT NULL,
  `who_has_booked` int(10) NOT NULL,
  `booked_for_whom` int(10) NOT NULL,
  `room_price` float(10,2) NOT NULL,
  `book_status` enum('0','1') NOT NULL DEFAULT '0',
  `booking_date` datetime NOT NULL DEFAULT '0000-00-00 00:00:00',
  `checkin_date` date NOT NULL,
  `checkin_time` int(4) NOT NULL,
  `checkout_date` date NOT NULL,
  `checkout_time` int(4) NOT NULL,
  PRIMARY KEY (`hotel_room_book_id`)
) ENGINE=MyISAM  DEFAULT CHARSET=latin1 AUTO_INCREMENT=20 ;

INSERT INTO hotel_room_book ( hotel_room_book_id , hotel_room_id , hotel_id , who_has_booked , booked_for_whom , room_price , book_status , booking_date , checkin_date , checkin_time , checkout_date , checkout_time ) VALUES (1, 13, 1, 1, 1, 564564.00, '0', '2011-06-15 00:00:00', '2011-06-15', 3, '2011-06-17', 12), (2, 13, 1, 1, 1, 564564.00, '0', '2011-06-15 00:00:00', '2011-06-17', 16, '2011-06-18', 3), (3, 13, 1, 1, 1, 23.00, '0', '2011-06-01 00:00:00', '2011-06-19', 5, '2011-06-20', 18);

Means room_id 13 is booked for

slno     checkin_date     checkin_time     checkout_date   checkout_time

 1        15-06-2011      3                 17-06-2011      12

 2        17-06-2011      16                18-06-2011      3

 3        19-06-2011      5                 20-06-2011      18

I am searching for

slno     checkin_date     checkin_time     checkout_date     checkout_time

1         17-06-2011       13                    17-06-2011       15

2        18-06-2011        4                     19-06-2011       4

3        14-06-2011        2                     15-06-2011       1

4        20-06-2011        19                    21-06-2011       2

I used the following logic for "room available" cases:

case1:(1,2,3 in above) Room is available

if required checkin_date and checkin_time >= booked checkout_date and checkout_time

and required checkout_date and checkout_time <= booked checkin_date and checkint_time

case2:(4 in above required date matches for availability) Room is available

if required checkin_date and checkin_time <= booked checkin_date and checkin_time

and required checkout_date and checkout_time <= booked checkin_date and checkint_time

My query is correct if I check manually,but I get zero record which is obvious. Hence can you please think on it and help me to find out the query which gives binary result yes/no or 1/0 for available/unavaible of that particular room during that particular period?

In Summary: Lets say room no 13 is booked from Dt-15-06-2011 at 3 to Dt-17-06-2011 at 12.

Again it is booked from Dt-17-06-2011 at 16 to Dt-18-06-2011 at 3. That means room number 13 is available for the duration Dt-17-06-2011 at 13 to Dt-17-06-2011 at 15.Now my question is avalability of room 13 is very clear from manual check.But what it is the mysql for it to check programaticaly.

Answer 1

SELECT * FROM hotel_room_book a , hotel_room_book b WHERE a.checkout_date<= 
 $new_checkin_date  AND b.checkin_date >= $new_checkout_date AND a.hotel_id = 
 b.hotel_id AND a.hotel_room_id = b.hotel_room_id ;

And this will work only if you have checkin_date and checkout_date as TIMESTAMP instead of date, as checking date and time separately will involve complex computation. (Hope you understand the problem in storing date and time in separate columns)

Answer 2

This query is Exactly Correct. ( Booking Date Column range) Just it running inverse.

 SELECT * FROM `bookings` WHERE `room_id` = 1  
 AND booking_end >= $from AND booking_start <= $to