如何匹配最长的字符串并更新值？

Question

I need to compare and match the longest match of two strings in two different tables and update one values if there is a closest match.

Table 1     Table 2
stack1     stack2
ABCDEFG    ABC
GHIJKLM    ABCDE
PQRSUVW    ABCDEF

I need to compare these two tables and match the closeet one and update Table 1 first row as ABCDEF the closest match, Please can anyone help me out. I am stuck here.

Here is my query

UPDATE table1 A 
   SET A.stack1 = (SELECT DISTINCT B.stack2 
                     FROM table2 B 
                    WHERE A.stack1 LIKE CONCAT(B.stack2,'%')) 
 WHERE name = 'name';

with this query am getting an error called

ORA-01427: single-row subquery returns more than one row

Answer 1

You need to make the subquery return only a single match (the longest one). In your case MAX should do that.

UPDATE table1 A 
SET A.stack1 = (SELECT Max( B.stack2 )
                 FROM table2 B 
                WHERE A.stack1 LIKE CONCAT(B.stack2,'%')) 
WHERE name = 'name';

Also, you should think about the case where nothing matches.

Answer 2

The ORA-01427 error is saying the subquery is returning more than one value -- even with the DISTINCT .

You need to correct the case(s) that are returning more than one distinct value. That could be with an aggregate function, like MAX or MIN , but without details I hesitate to make that recommendation.