jqEasy计数器（jquery）-需要“返回”计数为2个字符-如何？

Question

I'm using the jqEasy counter to countdown characters in a text area. http://web.archive.org/web/20150317063551/http://www.jqeasy.com/jquery-character-counter

In our implementation though--the database counts a return key as 2 characters while the counter only counts it as one. Basically the form submission takes the returns and makes them "/n" or something.

Does anyone have a recommendation on how I could modify this code to make the return key register 2 characters in the counter?

Thanks!

Answer 1

No you can't unless you change the code of the plugin. Right now the length of the input is calculated in this way (line 56) of the plugin:

    var val = $this.val(),
    length = val.length

Change it this way:

    var val = $this.val(),
    length = val.length
    //returns is an array: if i have two newline characters, it has three elemnts, 3 newline, four elements
    var returns = val.split('\n');
    length += returns.length -1;

What you sholud do is iterate over val and find out how many times the return key has been pressed and then sum that value to the lenght. Unfortunately i don't know how to find out "returns" in a string

EDIT - This is what you can do:

<textarea id='countIt'></textarea>

$('#countIt').keyup(function(){
    var value = $('#countIt').val();
    var returns = value.split('\n');
    var total = value.length;
    total += returns.length -1;
    console.log(total);//change with alert if no firebug
});

This should work, look at the fiddle http://jsfiddle.net/D27gs/2/

remember to attach this to the keyup event or it won't work