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关于SQLITE选择的BAD_ACCESS

[英]BAD_ACCESS on SQLITE selection

I am getting EXC_BAD_ACCESS when I attempt to do anything with the value I'm selecting from the local SQLITE database on an iPhone development. 当我尝试使用从iPhone开发中的本地SQLITE数据库中选择的值进行任何操作时,我得到EXC_BAD_ACCESS。 The code for my function is 我函数的代码是

-(void) updateFromDB {

// Setup the database object
sqlite3 *database;

// Open DB
if(sqlite3_open([databasePath UTF8String], &database) == SQLITE_OK) {

    NSString *query = [NSString stringWithFormat:@"SELECT MOD_ID FROM MODULE;"];

    //NSLog(@"QUERY: %@",query);

    // Prepare statement
    sqlite3_stmt *statement;
    if(sqlite3_prepare_v2(database, [query UTF8String], -1, &statement, NULL) == SQLITE_OK) {

        // Execute SQL
        while (sqlite3_step(statement) == SQLITE_ROW) {

            // Get MOD_IDs
            NSInteger MOD_ID = sqlite3_column_int(statement, 0);

            NSString *ID = [NSString stringWithFormat:@"%@",MOD_ID];

            //=======================
            // Get Notice Module Data
            //=======================
            if (MOD_ID == 1) {
                self.noticeModule = [[ModuleSetting alloc] initWithID:ID];
            }




        }

    } else {
        NSAssert1(0,@"Error: failed to prepare statement. '%s'", sqlite3_errmsg(database));
    }

    // Release the compiled statement from memory
    sqlite3_finalize(statement);

} else {
    sqlite3_close(database);
    NSAssert1(0,@"Failed to open database. '%s'",sqlite3_errmsg(database));
}
sqlite3_close(database);

}

The bad access occurs on the line 错误的访问发生在线路上

NSString *ID = [NSString stringWithFormat:@"%@",MOD_ID];

Thanks for any help you can offer! 谢谢你的尽心帮助!

%@ denotes objects. %@表示对象。 But MOD_ID seems to be an integer . 但是MOD_ID似乎是一个integer So your format should be %d , 因此,您的格式应为%d

NSString *ID = [NSString stringWithFormat:@"%d", MOD_ID];

You can't use %@ in format strings for integers, only for Obj-C objects. 您不能在整数格式字符串中使用%@ ,而只能用于Obj-C对象。 For integers, use %d (or for NSInteger, I think it is recommended to use %ld ). 对于整数,请使用%d (或对于NSInteger,我认为建议使用%ld )。

Have a look at the String Format Specifiers guide. 看看《 字符串格式说明符》指南。

MOD_ID不是指针,因此%@是不正确的。

Use below 在下面使用

 NSInteger MOD_ID = sqlite3_column_int(statement, 0);
   NSString *ID = [NSString stringWithFormat:@"%d",MOD_ID];

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