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删除节点的所有子节点

[英]Remove all child nodes of a node

I have a node of DOM document. 我有一个DOM文档的节点。 How can I remove all of its child nodes? 如何删除其所有子节点? For example: 例如:

<employee> 
     <one/>
     <two/>
     <three/>
 </employee>

Becomes: 变为:

   <employee>
   </employee>

I want to remove all child nodes of employee . 我想删除employee所有子节点。

No need to remove child nodes of child nodes 无需删除子节点的子节点

public static void removeChilds(Node node) {
    while (node.hasChildNodes())
        node.removeChild(node.getFirstChild());
}
public static void removeAllChildren(Node node)
{
  for (Node child; (child = node.getFirstChild()) != null; node.removeChild(child));
}
public static void removeAllChildren(Node node) {
    NodeList nodeList = node.getChildNodes();
    int i = 0;
    do {
        Node item = nodeList.item(i);
        if (item.hasChildNodes()) {
            removeAllChildren(item);
            i--;
        }
        node.removeChild(item);
        i++;
    } while (i < nodeList.getLength());
}

Just use: 只需使用:

Node result = node.cloneNode(false);

As document: 作为文件:

Node cloneNode(boolean deep)
deep - If true, recursively clone the subtree under the specified node; if false, clone only the node itself (and its attributes, if it is an Element).
private static void removeAllChildNodes(Node node) {
    NodeList childNodes = node.getChildNodes();
    int length = childNodes.getLength();
    for (int i = 0; i < length; i++) {
        Node childNode = childNodes.item(i);
        if(childNode instanceof Element) {
            if(childNode.hasChildNodes()) {
                removeAllChildNodes(childNode);                
            }        
            node.removeChild(childNode);  
        }
    }
}
    public static void removeAll(Node node) 
    {
        for(Node n : node.getChildNodes())
        {
            if(n.hasChildNodes()) //edit to remove children of children
            {
              removeAll(n);
              node.removeChild(n);
            }
            else
              node.removeChild(n);
        }
    }
}

This will remove all the child elements of a Node by passing the employee node in. 这将通过传递雇员节点来删除节点的所有子元素。

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