我可以使用SAX解析器解析二进制XML文件（在res / xml中）吗？

Question

To clarify my question :-)

I want to have the best of both worlds.

1. The speed of having a compressed xml file
2. The speed of the SAX parser ( over a XmlResourceParser that is normally used with binary files )

Most important question is: Can this be done?

Closest i came to the solution is.

• OR open a raw resource ( not binary formatted )
• OR parse a binary xml file with a XmlResourceParser

I hope someone can help me get a bit further in this situation.

Edit: link to reflect SAX-parser speed

Answer 1

SAX parser is not more efficient than XmlResourceParser for XML in raw resource. Just use XmlResourceParser.

Answer 2

You can place your xml file assets folder and you can use Sax parser

InputStream xmlFileStram = getAssets().open(filePath); // this gives the file in your asset folder
XmlHandler xmlHandler = new XmlHandler(activity);
SAXParserFactory.newInstance().newSAXParser().parse(xmlFileStram, xmlHandler);