[英]How to split a string of space separated numbers into integers?
I have a string "42 0"
(for example) and need to get an array of the two integers.我有一个字符串"42 0"
(例如)并且需要获取两个整数的数组。 Can I do a .split
on a space?我可以对空间进行.split
吗?
Use str.split()
:使用str.split()
:
>>> "42 0".split() # or .split(" ")
['42', '0']
Note that str.split(" ")
is identical in this case, but would behave differently if there were more than one space in a row.请注意, str.split(" ")
在这种情况下是相同的,但如果一行中有多个空格,则行为会有所不同。 As well, .split()
splits on all whitespace, not just spaces.同样, .split()
在所有空格上拆分,而不仅仅是空格。
Using map
usually looks cleaner than using list comprehensions when you want to convert the items of iterables to built-ins like int
, float
, str
, etc. In Python 2:当您想将可迭代项转换为内置函数(如int
、 float
、 str
等)时,使用map
通常比使用列表推导式看起来更简洁。在 Python 2 中:
>>> map(int, "42 0".split())
[42, 0]
In Python 3, map
will return a lazy object.在 Python 3 中, map
将返回一个惰性对象。 You can get it into a list with list()
:您可以使用list()
将其放入列表中:
>>> map(int, "42 0".split())
<map object at 0x7f92e07f8940>
>>> list(map(int, "42 0".split()))
[42, 0]
text = "42 0"
nums = [int(n) for n in text.split()]
l = (int(x) for x in s.split())
If you are sure there are always two integers you could also do:如果您确定总是有两个整数,您也可以这样做:
a,b = (int(x) for x in s.split())
or if you plan on modifying the array after或者如果您计划在之后修改数组
l = [int(x) for x in s.split()]
这应该有效:
[ int(x) for x in "40 1".split(" ") ]
Of course you can call split
, but it will return strings, not integers.当然你可以调用split
,但它会返回字符串,而不是整数。 Do做
>>> x, y = "42 0".split()
>>> [int(x), int(y)]
[42, 0]
or或者
[int(x) for x in "42 0".split()]
I have a string "42 0"
(for example) and need to get an array of the two integers.我有一个字符串"42 0"
(例如),需要获取两个整数的数组。 Can I do a .split
on a space?我可以在空格上进行.split
吗?
You can split and ensure the substring is a digit in a single line:您可以拆分并确保子字符串是一行中的数字:
In [1]: [int(i) for i in '1 2 3a'.split() if i.isdigit()]
Out[1]: [1, 2]
Other answers already show that you can use split() to get the values into a list .其他答案已经表明您可以使用split()将值放入list 。 If you were asking about Python's arrays , here is one solution:如果您问的是 Python 的arrays ,这是一种解决方案:
import array
s = '42 0'
a = array.array('i')
for n in s.split():
a.append(int(n))
Edit: A more concise solution:编辑:一个更简洁的解决方案:
import array
s = '42 0'
a = array.array('i', (int(t) for t in s.split()))
Given: text = "42 0"
给定: text = "42 0"
import re
numlist = re.findall('\d+',text)
print(numlist)
['42', '0']
I have a string "42 0"
(for example) and need to get an array of the two integers.我有一个字符串"42 0"
(例如),需要获取两个整数的数组。 Can I do a .split
on a space?我可以在空格上进行.split
吗?
I have a string "42 0"
(for example) and need to get an array of the two integers.我有一个字符串"42 0"
(例如),需要获取两个整数的数组。 Can I do a .split
on a space?我可以在空格上进行.split
吗?
Use numpy's fromstring
:使用 numpy 的fromstring
:
import numpy as np
np.fromstring("42 0", dtype=int, sep=' ')
>>> array([42, 0])
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