用空格分隔的bash字符串到数组

Question

I want to take a value read in and separate it from its spaces, then do stuff depending on the parts of the array. More exactly, if statement on the first (if false skip rest) 3 element will be changed from a word to a number using another program (a look up database) the 4th and last will check if there is a non-number or number above 64, if there isn't then it will combine it all back together (which I know how to do) then continue on. I have been working on this for over 3 hours now across multiple websites from Google.

vzybilly@vzybilly-laptop:~/Desktop$ cat ./test.sh
#!/bin/bash
read -p "cmd: " IN

#OIFS=$IFS
#IFS=';'
#arr2=$IN

#a=$(echo $IN | tr " " "\n")
a=$(echo "$IN")
for i in $(seq 0 $((4 - 1))); do
    echo "a[$i] = \"${a[$i]}\""
done

#IFS=$OIFS

exit 0
vzybilly@vzybilly-laptop:~/Desktop$ ./test.sh
cmd: cmd pers item num
a[0] = "cmd pers item num"
a[1] = ""
a[2] = ""
a[3] = ""

What I want:

vzybilly@vzybilly-laptop:~/Desktop$ ./test.sh
cmd: cmd pers item num
a[0] = "cmd"
a[1] = "pers"
a[2] = "item"
a[3] = "num"

Answer 1

Instead of

a=$(echo "$IN")

use

a=($IN)