[英]iPhone - adjusting the date on a UIDatePicker
I have the hour and the minute as NSIntegers (I don't care about the seconds... it may be 00) and I have a UIDatePicker adjusted to display just time (UIDatePickerModeTime). 我将小时和分钟作为NSIntegers(我不在乎秒...可能是00),并且将UIDatePicker调整为仅显示时间(UIDatePickerModeTime)。
Simple question: how do I set an hour on the UIDatePicker? 一个简单的问题:如何在UIDatePicker上设置一个小时? Hours are in the 24h format (as it comes from the picker naturally).
小时采用24小时制(因为它自然来自选择器)。
Suppose this: 假设这:
NSInteger hour = 17;
NSInteger minute = 12;
[myTimePicker setDate: ????];
I know I have to convert that hour and minute to NSDate, but how do I do that without including a day? 我知道我必须将小时和分钟转换为NSDate,但是如何在不包括一天的情况下进行转换呢? I just need time.
我只需要时间
I have read this example , but it also considers the day. 我已经阅读了这个示例 ,但是它也考虑了这一天。
How do I construct a NSDate of just time, so I can adjust my UIDatePicker? 我该如何构造一个NSDate时间,以便可以调整UIDatePicker?
thanks 谢谢
You should be able to do this, 您应该能够做到这一点,
NSCalendar * gregorian = [[[NSCalendar alloc] initWithCalendarIdentifier:NSGregorianCalendar] autorelease];
NSDateComponents * dateComponents = [[[NSDateComponents alloc] init] autorelease];
[dateComponents setHour:17];
[dateComponents setMinute:12];
myTimePicker.date = [gregorian dateFromComponents:dateComponents];
You can later get the hour and minute like this, 以后您可以这样获取小时和分钟,
NSCalendar * gregorian = [[[NSCalendar alloc] initWithCalendarIdentifier:NSGregorianCalendar] autorelease];
NSDateComponents * dateComponents = [gregorian components:(NSHourCalendarUnit|NSMinuteCalendarUnit) fromDate:myTimePicker.date];
int hour = [dateComponents hour];
int minute = [dateComponents minute];
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