[英]How to match with an exact string using regular expression
I have small requirement.I want to search a string with exact match. 我的要求很小。我想搜索一个完全匹配的字符串。 Suppose i want to search for None_1, i am searching for 'None_1' using /None_1/, but it is matching even "xxxNone" but my requirement is it should match only None_[any digit]. 假设我想搜索None_1,我正在使用/ None_1 /搜索'None_1',但它甚至匹配“xxxNone”但我的要求是它应该只匹配None_ [任何数字]。 Here is my code 这是我的代码
/^None_+[0-9]{?}/
So it should match only None_1 , None_2 所以它应该只匹配None_1,None_2
You should also anchor the expression at the end of the line. 您还应该将该表达式锚定在该行的末尾。 But that alone will not make it work. 但仅凭这一点就无法发挥作用。 Your expression is wrong. 你的表达是错的。 I think it should be: 我认为它应该是:
/^None_[0-9]+$/
^
matches the beginning of a line ^
匹配一行的开头 [0-9]+
matches one or more digits [0-9]+
匹配一个或多个数字 None_
matches None_
None_
匹配无None_
$
matches the end of a line $
匹配一行的结尾 If you only want to match one digit, remove the +
. 如果您只想匹配一位数,请删除+
。
Your original expression /^None_+[0-9]{?}/
worked like this: 您的原始表达式/^None_+[0-9]{?}/
工作方式如下:
^
matches the beginning of a line ^
匹配一行的开头 None
matches None
None
匹配None
_+
matches one or more underscores _+
匹配一个或多个下划线 [0-9]
matches one digit [0-9]
匹配一位数 {?
matches an optional opening bracket {
匹配可选的左括号{
}
matches }
}
匹配}
尝试这个:
/^None_+[0-9]{?}$/
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