[英]regular expression to use in PHP for removing particular text in brackets from a text string
Can't figure this one out... I need a regular expression to use in PHP for removing particular text from a text string... 无法弄清楚这一点...我需要一个正则表达式在PHP中使用以从文本字符串中删除特定文本...
My text strings are like this: "The product we're talking about [Art.0430000] is a good product" "The product we're talking about [Art.0430001] is a good product" "The product we're talking about [Art.7852000] is a good product" 我的文字字符串是这样的:“我们正在谈论的产品[Art.0430000]是一个好产品”“我们正在谈论的产品[Art.0430001]是一个好产品”关于[Art.7852000]是个好产品“
I need to remove [Art.0430000], [Art.0430001], [Art.7852000] from the strings... 我需要从字符串中删除[Art.0430000],[Art.0430001],[Art.7852000] ...
The regular expression should be: 正则表达式应为:
\[Art\.[0-9]+\]
(In words: The literal string "[Art.", followed by one or more numerals in the range 0-9, followed by the literal string "]".) (换句话说:文字字符串“ [Art。”,后跟0-9范围内的一个或多个数字,后跟文字字符串“]”。)
In PHP: 在PHP中:
$pattern = '/\[Art\.[0-9]+\]/';
$result = preg_replace($pattern, "", $string);
我没有测试过,但是应该可以工作:
preg_replace_all("/\[Art(^\]+)\]/", "", $string);
If you also want to compress the white space left over (2 spaces to 1 space); 如果您还想压缩剩余的空白(将2个空间压缩为1个空间);
$pattern = '/\[Art\.[0-9]+\]\s*/';
$result = preg_replace($pattern, "", $string);
$pattern = "#\\[Art\\.([o-9])+\\]#"; $ pattern =“#\\ [艺术\\。([o-9])+ \\]#”; str_replace($pattern,"",$str);
str_replace($ pattern,“”,$ str);
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