php 分页问题怎么办？

Question

i am trying to do some pagination for my website and i'm using this tutorial and i run in a few problems.

first, this is how i find out the total nr of results:

$total_records_left = 'SELECT COUNT(*) FROM `comments` WHERE `post_id_fk` = 1';
$results_left = mysql_query($total_records_left) or die('Sorry, we could not count the number of results: ' . mysql_error());
$numberofresults_left = mysql_result($results_left, 0);

$numberofresults_left will return lets say 20 records

now, if i fallow the tutorial, at one point i see that i need to declare this vars:

$pages = new Paginator;  
$pages->items_total = $num_rows[0];  
$pages->mid_range = 9;  
$pages->paginate();  
echo $pages->display_pages();  

I don't understand how to connect my $numberofresults_left with those vars. How is the paginator.class.php is gonna know how many pages do i have?

also i see this query at one point: SELECT title FROM comments WHERE title != '' ORDER BY title ASC $pages->limit but there is no variable connected to it. Where i am gonna use this?

Please make me understand how this actually works Thanks

Answer 1

I think you've got a couple variables mixed up. $numberofresults_left looks as though it should be called $num_rows . As for the latter part of your question, $pages is the instance of the Paginator class, and ->limit is the public property that records the limit when the object was created.

Towards the end of the article you're following, you should read the following:

$pages->limit is critical in making everything work and allows our paginator object to tell the query to fetch only the limited number of records that we need. For example, if we wanted to see page seven of our data, and we're viewing 25 items per page, then $pages->limit would be the same as LIMIT 150,25 in SQL.