如何使用正则表达式删除字符第二次出现之外的所有内容？

Question

I have a list that is something like:

xxxxx|xxxxxx|xxxxx@example.com
xxxxx|xxxxxx|xxxxx@example.com
xxxxx|xxxxxx|xxxxx@example.com

The x's can be both letters and numbers, but nothing else.

What I am trying to do is replace everything (including the character) to the right of the second | . The outcome should look like:

xxxxx|xxxxx

I want to do it with regex so that I can replace all the occurrences in Notepad++.

Answer 1

Find

^([^|]*|[^|]*)|.*$

Replace with

\1

Reference: http://www.scintilla.org/SciTERegEx.html

Answer 2

Replace \|[^\|]+$ with nothing.

This will match |xxxxx@example.com , so if you replace it with a blank string, that will accomplish what you want.