从 C++ DLL 获取函数名称

Question

I have function declared as __declspec(dllexport) void TakeInput();

The DLL which has this function is exported in C#.I am getting failure while executing function call to this function as entry point not found in c# code.

Googling shows that issue is with correct entry point is not provided.I will need to provide mangled name for this function.

So I would like to know how can I get mangled name of this function?

Answer 1

in order to avoid name mangling, use extern "C"

extern "C" __declspec(dllexport) void TakeInput();

More reading: Using extern to specify linkage

Answer 2

You can use DependancyWalker (http://www.dependencywalker.com) or some other tool that lists DLL exports to get the mangled name if you really want to, but you're best doing what Armen suggested.

Answer 3

Instead of trying to compute the mangled name, I suggest to just export the unmangled name. Do do this, you need to do two things:

1. Disable C++ name mangling by using C linkage for your function You can do this by using extern "C" .

2. Ensure that your function is using the C calling convention. This is the default (at least with Microsoft Visual Studio) but this default can be changed using the /Gr (which toggles the __fastcall calling convention) and /Gz (which toggles the __stdcall calling convention) command line switches. You can enforce the C calling convention using __cdecl like this:

So all in all, to ensure that your function is exported as TakeInput , use:

extern "C" __declspec(dllexport) void __cdecl TakeInput();