如何获取javascript或jquery中相同属性的不同值的元素？

Question

I need to find elements with the different value of the same attribute... This works-> $data.find("div[data-alpha='1']"); But i need something like this-> $data.find('div[data-alpha='1']' + 'div[data-alpha='2'] ' .... So i want to find all elements which have the,,data-alpha" atribute 1 or 2. Anyone have an idea how to do that? Thanks for all answers! Cheers!

Answer 1

Use the multiple-selector ^[docs] .

$data.find("div[data-alpha='1'], div[data-alpha='2']")

This allows you to accumulate the results of different selectors by joining the selectors with a comma into a single selector.

Answer 2

Try the add() method ( http://api.jquery.com/add/ ).

Answer 3

If you want to find all elements with the data-alpha attribute use

$data.find([data-alpha])

If you need elements with specific values, use:

$data.find([data-alpha=x],[data-alpha=y])