[英]Javascript replacing string pattern using RegExp?
I want to remove any occurances of the string pattern of a number enclosed by square brackets, eg [1], [25], [46], [345] (I think up to 3 characters within the brackets should be fine).我想删除任何出现在方括号内的数字的字符串模式,例如 [1]、[25]、[46]、[345](我认为括号内最多 3 个字符应该没问题)。 I want to replace them with an empty string, "", ie remove them.
我想用空字符串“”替换它们,即删除它们。
I know this can be done with regular expressions but I'm quite new to this.我知道这可以用正则表达式来完成,但我对此很陌生。 Here's what I have which doesn't do anything:
这是我没有做任何事情的东西:
var test = "this is a test sentence with a reference[12]";
removeCrap(test);
alert(test);
function removeCrap(string) {
var pattern = new RegExp("[...]");
string.replace(pattern, "");
} }
Could anyone help me out with this?谁能帮我解决这个问题? Hope the question is clear.
希望问题很清楚。 Thanks.
谢谢。
[]
has a special meaning in regular expressions, it creates a character class . []
在正则表达式中有特殊含义,它创建一个字符 class 。 If you want to match these characters literally, you have to escape them.如果你想从字面上匹配这些字符,你必须对它们进行转义。
replace
[docs] only replaces the first occurrence of a string/expression, unless you set the global flag/modifier. replace
[docs]仅替换第一次出现的字符串/表达式,除非您设置全局标志/修饰符。
replace
returns the new string, it does not change the string in-place. replace
返回新字符串,它不会就地更改字符串。
Having this in mind, this should do it:考虑到这一点,应该这样做:
var test = "this is a test sentence with a reference[12]";
test = test.replace(/\[\d+\]/g, '');
alert(test);
Regular expression explained:正则表达式解释:
In JavaScript, /.../
is a regex literal .在
/.../
中,/.../ 是正则表达式文字。 The g
is the global flag. g
是全局标志。
\[
matches [
literally \[
匹配[
字面意思\d+
matches one or more digits \d+
匹配一位或多位数字\]
matches ]
literally \]
匹配]
字面意思To learn more about regular expression, have a look at the MDN documentation and at http://www.regular-expressions.info/ .要了解有关正则表达式的更多信息,请查看MDN 文档和http://www.regular-expressions.info/ 。
This will do it:这将做到:
test = test.replace(/\[\d+\]/g, '');
\[
because [
on its own introduces a character range \[
因为[
本身引入了一个字符范围\d+
- any number of digits \d+
- 任意位数\]
as above \]
如上/g
- do it for every occurrence /g
- 每次出现都这样做NB: you have to reassign the result (either to a new variable, or back to itself) because String.replace
doesn't change the original string.注意:你必须重新分配结果(要么给一个新变量,要么给它自己),因为
String.replace
不会改变原始字符串。
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