[英]ostream operator overloading for unsigned char in C++
Given:鉴于:
typedef struct { char val[SOME_FIXED_SIZE]; } AString;
typedef struct { unsigned char val[SOME_FIXED_SIZE]; } BString;
I want to add ostream operator <<
available for AString
and BString
.我想添加 ostream 运算符
<<
可用于AString
和BString
。
std::ostream & operator<<(std::ostream &out, const AString &str)
{
out.write(str.val, SOME_FIXED_SIZE);
return out;
}
If I do the same for BString
, the compiler complains about invalid conversion from 'const unsigned char*' to 'const char*'
.如果我对
BString
做同样的事情,编译器会抱怨invalid conversion from 'const unsigned char*' to 'const char*'
。 The ostream.write
does not have const unsigned char*
as argument. ostream.write
没有const unsigned char*
作为参数。
It seems <<
itself accepts the const unsigned char
, so I try something like this似乎
<<
本身接受const unsigned char
,所以我尝试这样的事情
std::ostream & operator<<(std::ostream &out, const BString &str)
{
for (int i=0; i<SOME_FIXED_SIZE; i++)
{
out<<str.val[i];
}
return out;
}
Can someone tell me if this is right/good practice or there are some better ways?有人可以告诉我这是正确/好的做法还是有更好的方法? welcome any comments!
欢迎任何意见!
The simplest and cleanest solution is to create an std::string
, eg:最简单和最干净的解决方案是创建一个
std::string
,例如:
out << std::string(str.val, str.val + sizeof(str.val));
However, the question is: do you want formatted or unformatted output?但是,问题是:您要格式化还是未格式化的 output? For unformatted output, as ugly as it is, I'd just use a
reinterpret_cast
.对于未格式化的 output,尽管它很丑,但我只会使用
reinterpret_cast
。
Have you thought about casting it to char*
:您是否考虑过将其转换为
char*
:
std::ostream & operator<<(std::ostream &out, const BString &str)
{
out.write(reinterpret_cast<char*>(str.val), sizeof(str.val));
return out;
}
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