[英]How match a regex if it does not contain a particular word?
I want to write a regex in Python or JavaScript to match if the given string does not JUST contain the given word (eg "any").如果给定的字符串不只包含给定的单词(例如“任何”),我想在 Python 或 JavaScript 中编写一个正则表达式来匹配。
For example:例如:
any
: does not match any
:不匹配AnY
: does not match AnY
: 不匹配anyday
: match anyday
:比赛any day
: match any day
:比赛blabla
: match blabla
: 匹配
If you also need words other that starting with "any" you can use a negative lookahead如果您还需要以“any”开头的单词,则可以使用否定前瞻
^(?!any$).*$
This will match anything besides "any".这将匹配除“any”之外的任何内容。
It is probably more efficient to not use a regex, this works as well:不使用正则表达式可能更有效,这也有效:
def noAny(i):
i = i.lower().replace('any', '')
return len(i) > 0
Something like this:像这样的东西:
/(any)(.+)/i
any.+
..and some text to make the 30char threshold ..和一些文字来制作 30char 阈值
Use string.match(regexp)
method in javascript for this purpose.为此,在 javascript 中使用
string.match(regexp)
方法。 See the code below:请看下面的代码:
<script type="text/javascript">
var str="source string contains YourWord";
var patt1=/YourWord/gi; // replace YourWord within this regex with the word you want to check.
if(str.match(patt1))
{
//This means there is "YourWord" in the source string str. Do the required logic accordingly.
}
else
{
// no match
}
</script>
Hope this helps...希望这可以帮助...
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