如何在 C++ 中解析命令行 arguments？

Question

How to effectively parse this command line in C++?

program -parameter1=value1 -parameter2=value2 -parameter3=value3

How to effectively drop a combination of the parameter and value

-parameter=value

I am trying to use this code but it does not work properly:

parameter[256], value[256],
while ( --argc > 0 )
{
   if ( *argv[argc] == '-' )
   {
       for ( char * text = argv[argc]; ; )
       {    
            switch ( * ( ++ text ) )
            {
                case '=' :
                {
                   *value = *(  text );
                    break;
                }

                default:
                {
                   *parameter = *text;
                }
            }
         }

       //Testing parameters and values
    }
}

Thanks for your comments and improvements.

Answer 1

Did you consider boost::program_options or if you can't use boost, getopt_long ?

Answer 2

I've leveraged TCLAP ( Templatized C++ Command Line Parser Library ) in many C++ based command line apps and been very happy with it, but it might not give you all the flexibility to read the parameters in the format you are looking at, but still worth a look, boost::program_options is a good suggestion also.

Answer 3

You can do this a lot more transparently with std::string and functions like find_first_of , splitting off the different parts and have the nice bonus that each time a find function returns std::string::npos , you know you've got an invalid argument.

Answer 4

I'd advise you to use the standard C library for argument parsing: there is a premade function called getopt for that.

Answer 5

*value = *( text ); This line only writes one character.