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将此 if-then 逻辑转换为 boolean 表达式?

[英]Turn this if-then logic into a boolean expression?

I'm having a bit of a brain fart on making this code more concise(preferably a single boolean expression)我在使这段代码更简洁方面有点放屁(最好是单个 boolean 表达式)

This is my code:这是我的代码:

                    if (d.Unemployed)
                    {
                        if (type.Unemployed)
                        {
                            tmp.Unemployed = true;
                        }
                        else
                        {
                            tmp.Unemployed = false;
                        }
                    }
                    else
                    {
                        if (type.Unemployed)
                        {
                            tmp.Unemployed = false;
                        }
                        else
                        {
                            tmp.Unemployed = true;
                        }
                    }

Basically the point is that if either type or d is not unemployed, then tmp should be set to not unemployed.基本上要点是,如果typed没有失业,则tmp应设置为未失业。

How about:怎么样:

tmp.Unemployed = type.Unemployed == d.Unemployed;

If we construct a truth table by following the code, we get如果我们按照代码构造一个真值表,我们得到

d  | type | tmp
---+------+----
1  |   1  |  1
---+------+----
1  |   0  |  0
----+-----+----
0  |   1  |  0
----+-----+----
0  |   0  |  1

The above is equivalent with the negation of the xor operation.以上等价于xor或运算的否定。

tmp = not (d xor type)

If the language doesn't have the xor operator we can use the != on boolean values.如果语言没有xor运算符,我们可以在 boolean 值上使用!=

tmp = ! (d != type);
// or
tmp = d == type;

Thinking about how much "brain fart" this caused you I would consider using a well named variable to avoid having to go through this mental process again in future.考虑到这给你造成了多少“大脑放屁”,我会考虑使用一个命名良好的变量,以避免将来再次通过这个心理过程进行 go。 Something like this:像这样的东西:

isTmpUnemployed = (type.Unemployed == d.Unemployed);
tmp.Unemployed = isTmpUnemployed;
tmp.Unemployed = d.Unemployed || type.Unemployed ? !tmp.Unemployed : null;

The above code means "both unemployed or both not unemployed".上述代码的意思是“都失业或都没有失业”。 Thus, not (A xor B):因此,不是(A xor B):

 tmp.Unemployed = ! ( D.Unemployed ^ type.Unemployed)

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