简体   繁体   English

如何在 iphone 中打开 UIWebView 中的链接

[英]How to open links in UIWebView in iphone

I want to open a link in my application and I don't want to close my application aw well.我想在我的应用程序中打开一个链接,我不想很好地关闭我的应用程序。 I have navigation bar on top of application and just below the navigation I want to open my web view.我在应用程序顶部有导航栏,在导航下方我想打开我的 web 视图。 I have defined my outlet.我已经定义了我的出口。

 IBOutlet  UIWebView *displaySingleData;

How will I open an link in my application.我将如何在我的应用程序中打开链接。

Thanks in advance提前致谢

NSString *urlAddress = @”http://www.google.com”;

//Create a URL object.
NSURL *url = [NSURL URLWithString:urlAddress];

//URL Requst Object
NSURLRequest *requestObj = [NSURLRequest requestWithURL:url];

//Load the request in the UIWebView.
[webView loadRequest:requestObj];

jst write following code:只需编写以下代码:

[displaySingleData loadRequest:[NSURLRequest requestWithURL:[NSURL URLWithString:@"http://www.google.com"]]];

Happy coding..快乐的编码..

声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.

 
粤ICP备18138465号  © 2020-2024 STACKOOM.COM