如何将“YYYY-MM-DD hh:mm:ss”格式的日期转换为 UNIX 时间戳

Question

How can I convert a time in the format "YYYY-MM-DD hh:mm:ss" (eg "2011-07-15 13:18:52" ) to a UNIX timestamp?

I tried this piece of Javascript code:

date = new Date("2011-07-15").getTime() / 1000
alert(date)

And it works, but it results in NaN when I add time('2011-07-15 13:18:52') to the input.

Answer 1

Use the long date constructor and specify all date/time components:

var match = '2011-07-15 13:18:52'.match(/^(\d+)-(\d+)-(\d+) (\d+)\:(\d+)\:(\d+)$/)
var date = new Date(match[1], match[2] - 1, match[3], match[4], match[5], match[6])
// ------------------------------------^^^
// month must be between 0 and 11, not 1 and 12
console.log(date);
console.log(date.getTime() / 1000);

Answer 2

Following code will work for format YYYY-MM-DD hh:mm:ss :

function parse(dateAsString) {
    return new Date(dateAsString.replace(/-/g, '/'))
}

This code converts YYYY-MM-DD hh:mm:ss to YYYY/MM/DD hh:mm:ss that is easily parsed by Date constructor.

Answer 3

You've accepted an answer, but a much simpler regular expression can be used:

function stringToDate(s)  {
  s = s.split(/[-: ]/);
  return new Date(s[0], s[1]-1, s[2], s[3], s[4], s[5]);
}

alert(stringToDate('2011-7-15 20:46:3'));

Of course the input string must be the correct format.

Answer 4

Months start from 0, unlike the days! So this will work perfectly ( tested )

function dateToUnix(year, month, day, hour, minute, second) {
    return ((new Date(Date.UTC(year, month - 1, day, hour, minute, second))).getTime() / 1000.0);
}

Answer 5

This returns number of milliseconds since Jan. 1st 1970: Date.parse('2011-07-15 10:05:20')

Just divide by 1000 to get seconds instead of milliseconds..