操作方法：使用图表 API 将照片上传到用户的个人资料

Question

I am developing an application which uploads images into user's profile.I manage to do this by referring this blog

https://developers.facebook.com/blog/post/498/

Everything works fine and display the 'id' of the uploaded image.

Now I want to take this id into a variable and pass it to another file without displaying 'id' of the image(Lets say I want to pass this id into a.php file and display the 'id' using 'echo' command).

Can any one help me to do this? I think this is not a difficult task.Since I have vary poor knowledge about php, I cannot figure out any way.

Can any one please please help me to solve this problem.

Thanks.

Answer 1

What do you mean by "pass into another php file?" If you mean reload the page but with passing the ID you can use $_GET array.

Simply, after receiving the id from uploaded photo you can call function:

header('location : http://yourdomain.com/a.php?id='.$id_of_photo);

and then in a.php you can get it by accessing $_GET array

if(isset($_GET['id'])) {
  echo 'uploaded photo id is: '.$_GET['id'];
}