C# 二进制数组“{ 84, 01, 00, 00 }” 在 Windows 注册表中更改为“54 01 00 00”

Question

I'm using C# to write the following binary value to the system registry:

  byte[] valueToSet = { 84, 01, 00, 00 };
  Registry.SetValue(keyName, "00036601", valueToSet);
  // returns void as expected.

When I view the written value using regedit, I see the displayed value as 54 01 00 00. This is incorrect

Conversely when I set the value to 84,01,00,00 manually in the registry, and run this code

object ttt = Registry.GetValue(keyName, "00036601", null);
// returns 132, 1, 0, 0

Is this an Endian issue? What is the correct way to fix this?

Answer 1

It's a hexadecimal issue. RegEdit displays values in hexadecimal, and you're working with decimal in C#.

The two values are equivalent:

0x54 == 84

Answer 2

The registry editor displays the value in hexadecimal. The decimal value 84 is equal to the hexadecimal value 0x54, and hexadecimal 0x84 is equal to decimal 132.

Answer 3

I think you are trying to specify the literals in hex . However, without the 0x hex-prefix, the compiler interprets them as decimals .

Try this instead:

byte[] valueToSet = { 0x84, 0x01, 0x00, 0x00 };

Answer 4

The values shown in the registry for binary types are in hexidecimal notation. Decimal 84 == hex 0x54.

Answer 5

interesting thing to note is that 84 (decimal) == 54 (hex)