PHP - 如何提交包含指向不同 MySQL 行的输入字段的表单

Question

I am setting up a form using this PHP that loops through all records a user may have:

    <?php foreach ($items as $row): ?>
            <tr>
                <td>
                    <?php echo form_hidden('id', $row->id); ?>
                </td>
                <td>
                    <?php echo '<strong>' . $row->name . '</strong>'; ?>
                </td>
                <td>
                    <?php echo form_input('number', $number); ?>
                </td>
                <td>
                    <?php echo form_input('registry', $registry); ?>
                </td>
                <td>
                    <?php echo form_checkbox('OK', $ok, $ok); ?>
                </td>
            </tr>
    <?php endforeach; ?>

This gives me a form with the following look:

The idea here is that each row belongs to a unique ID/row in the database, and I would like to allow the user to edit all on the same page/form, using a single submit button.

What would be the best way of implementing this?

When this data is submitted, there should be a way of looping through each packet of information (from each user) in my controller. Would this be done via ajax/json?

Answer 1

There's no need to use ajax mate.

For each put a hidden input with the ID of the row in this format:

<input type="hidden" name="id[<?= $row->id ?>]" value="<?= $row->id ?>" ?>

Do the same for each element in the tr, ie name them as

name="number[<?= $row->$id ?>]"
name="registry[<?=$row->$id ?>]"
name="ok[<?=$row->$id ?>]"

and once you post the FORM you can iterate each row with:

foreach ($_POST['id'] as $key => $value) {
    echo $_POST['name'][$key];
}

Answer 2

This does not use codeigntier, but you should be familiar with the general technique before attempting to use CI to shortcut this process. Codeigniter will help you with rendering the form elements, performing validation, escaping your input and performing your query - but it will only help you (do anything) if you understand the basic principles involved. Hope this helps

MARKUP

<form action="/process.php">
<div>
    <h2>GORDON</h2>
    <input type="text" name="user[1][number]" /> <!-- The number corresponds to the row id -->
    <input type="text" name="user[1][registry]" />
    <input type="checkbox" name="user[1][ok]" value="1" />
</div>
<div>
    <h2>ANDY</h2>
    <input type="text" name="user[242][number]" />
    <input type="text" name="user[242][registry]" />
    <input type="checkbox" name="user[242][ok]" value="1" />
</div>
<div>
    <h2>STEWART</h2>
    <input type="text" name="user[11][number]" />
    <input type="text" name="user[11][registry]" />
    <input type="checkbox" name="user[11][ok]" value="1" />
</div>

<input type="submit" />

PHP

$users = $_REQUEST['user'];

foreach ($users as $rowId => $info){

    // YOU SHOULD MAKE SURE TO CLEAN YOUR INPUT - THIS IS A GUESS AT WHAT YOUR DATA TYPES MIGHT BE
    $id = (int) $rowId;
    $number = (int) $info['number'];
    $registry = mysql_real_escape_string($info['registry']);
    $ok = (int) ($info['ok']);

    $q = "UPDATE user SET number = $number, registry = '$registry', ok = $ok WHERE id = $id";
    mysql_query($q);

    // You may want to check that the above query was sucessful and log any errors etc.

}

Answer 3

You need to set up input-names as array-names, so you will send the whole form and may iterate over the entries.

eg

<?php
echo form_input('userdata[' . $row->id . '][number]', $number);
?>

which would possibly create an

<input name="userdata[1][number]" />

(I don't know where those form-functions came from…)

This will result in an array $_POST['userdata'] which may be iterated via:

foreach($_POST['userdata'] as $userId => $userInputFields)
{
    $user = new User($userId);
    $user->number = $userInputFields['number'];
    // …
}