[英]java.io.IOException: Not in GZIP format with class.getResourceAsStream()
I am trying to load some GZIP-ed data from a resource in my.jar, but I get a java.io.IOException: Not in GZIP
format message.我正在尝试从 my.jar 中的资源加载一些 GZIP 数据,但我收到
java.io.IOException: Not in GZIP
格式消息。
When I load the same data from a file, I don't get any error.当我从文件加载相同的数据时,我没有收到任何错误。 Why?
为什么? (It is a maven project I compile with NetBeans)
(是我用NetBeans编译的maven项目)
Here is the test code generating the issue:这是生成问题的测试代码:
public static void main(String[] args) throws IOException {
byte[] dummy = new byte[10];
// Reading data from file
File f = new File("C:\\Temp\\422\\convert1900.data");
DataInputStream is = new DataInputStream(
new GZIPInputStream(new FileInputStream(f)));
while ( is.read(dummy) != -1 );
// Reading data from resource
InputStream ins = CompareTest2.class.getResourceAsStream(
"/net/cv/convert1900.data");
is = new DataInputStream(
new GZIPInputStream(ins)); // Issue happens here
while ( is.read(dummy) != -1 );
}
EDIT编辑
Both 'files' have the same content.两个“文件”具有相同的内容。
EDIT 2编辑 2
I just tried to count the number of bytes I get with both methods using the following code:我只是尝试使用以下代码计算两种方法获得的字节数:
public static void main(String[] args) throws IOException {
int total = 0;
int retr = 0;
byte[] dummy = new byte[10];
// Reading data from file
File f = new File("C:\\Temp\\422\\convert1900.data");
InputStream is = new FileInputStream(f);
do {
retr = is.read(dummy);
if ( retr != -1 )
total += retr;
} while ( retr != -1 );
System.out.println("Total file: " + total);
// Reading data from resource
InputStream ins = CompareTest2.class.getResourceAsStream(
"/net/cv/convert1900.data");
total = 0;
retr = 0;
do {
retr = ins.read(dummy);
if ( retr != -1 )
total += retr;
} while ( retr != -1 );
System.out.println("Total resource: " + total);
}
and I get:我得到:
Total file: 9132744
Total resource: 16399085
Very strange !!很奇怪 !!
EDIT 3编辑 3
I have just noticed the size of the resource in the.jar is 16399085 (uncompressed) instead of 9132744. It seems that the issue is in the compilation process.刚刚注意到.jar中的资源大小是16399085(未压缩)而不是9132744。看来问题出在编译过程中。
May be I have an issue with the following in my pom.xml:可能是我的 pom.xml 中有以下问题:
<plugin>
<groupId>org.apache.maven.plugins</groupId>
<artifactId>maven-resources-plugin</artifactId>
<version>2.5</version>
<configuration>
<encoding>${project.build.sourceEncoding}</encoding> // UTF8
</configuration>
</plugin>
I compiled your code and can't reproduce your situation.我编译了您的代码,无法重现您的情况。 My code snippet follows.
我的代码片段如下。
Try to assert that you get proper data thru getResourceAsStream - for example dump it to a file without un-gzip and reload it using the File approach.尝试断言您通过 getResourceAsStream 获得了正确的数据 - 例如,将其转储到没有 un-gzip 的文件并使用 File 方法重新加载它。 Might be you have the /net/cv/convert... visible twice in your classpath and the runtime gets the wrong one?
可能你的 /net/cv/convert... 在你的类路径中可见两次并且运行时得到了错误的?
java version "1.6.0_26"
Java(TM) SE Runtime Environment (build 1.6.0_26-b03-384-10M3425)
Java HotSpot(TM) 64-Bit Server VM (build 20.1-b02-384, mixed mode)
javac A.java
java -cp mega.jar:. A
import java.io.DataInputStream;
import java.io.File;
import java.io.FileInputStream;
import java.io.IOException;
import java.io.InputStream;
import java.lang.IllegalStateException;
import java.util.zip.GZIPInputStream;
public class A {
public static void main(String[] args) throws IOException {
final byte[] dummy = new byte[10];
// Reading data from file
final File f = new File("/tmp/mine.data");
DataInputStream is = new DataInputStream(new GZIPInputStream(new FileInputStream(f)));
int count = 0;
while (is.read(dummy) != -1) count++;
System.out.println("count = " + count);
// Reading data from resource
InputStream ins = A.class.getResourceAsStream("/do/do/mine.data");
if (ins == null)
throw new IllegalStateException("Failed to locate data.");
is = new DataInputStream(new GZIPInputStream(ins)); // Issue happens here
count = 0;
while (is.read(dummy) != -1) count++;
System.out.println("count = " + count);
}
}
I am pretty sure that line InputStream ins = CompareTest2.class.getResourceAsStream("/net/cv/convert1900.data");
我很确定
InputStream ins = CompareTest2.class.getResourceAsStream("/net/cv/convert1900.data");
returns null.返回 null。 Check this.
检查这个。 If so check your pass
/net/cv/convert1900.data
, check your jar, verify the classpath when running from maven: probably the resource is not there.如果是这样,请检查您的通行证
/net/cv/convert1900.data
,检查您的 jar,从 maven 运行时验证类路径:可能资源不存在。
BTW it is possible.顺便说一句,这是可能的。 All resources in maven must be under directory resources?
maven中的所有资源都必须在目录资源下吗? Is it correct for your project.
它是否适合您的项目。 If for example resource files are under main/java they will not be copied to target directory.
例如,如果资源文件位于 main/java 下,它们将不会被复制到目标目录。
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