严格标准错误

Question

The function parse_users returns an array.

I am doing the following in another function:

return reset($this->parse_users($records));

But I get a Strict Standards: Only variables should be passed by reference in...

Is it because I do a reset() on the function?

Do I have to do it this way:

$users = $this->parse_users($records);
return reset($users);

Or is something else?

Answer 1

That's it exactly. reset takes a reference to an array as a parameter, so it basically needs a real variable to reference -- even if it is a pass-by-reference value.

Answer 2

why didn't you try your

$users = $this->parse_users($records);
return reset($users);

?

It's correct

Answer 3

The one-line-solution uses an additional pair of brackets; this will turn the reference into a variable and omit the error:

return reset( ( $this->parse_users($records) ) );

Answer 4

From the PHP documentation for reset :

mixed reset ( array &$array )

reset() rewinds array's internal pointer to the first element and returns the value of the first array element.

The PHP reset() function accepts a reference to an array. The strict warning is raised because you're directly passing the result of parse_users to reset, without a way to access that array in your other function.

If you're trying to return the full array (and not just the first value) after it's been reset, you should use:

$users = $this->parse_users($records);
reset($users);

return $users;

Alternatively, if you just want the first value from parse_users, you could just use:

$users = $this->parse_users($records);
return $users[0];

The reset function is only needed when you're iterating over the array and want to make sure you start from the beginning.