我的应用程序使用 web 服务器来保存数据并将其加载到数据库中，如何在不单击提交按钮的情况下保存表单？
[英]My app using web server inorder to save and load data to the database how can i save the form without click the submit button?
问题描述
I have a iphone application when the user presses the button i collect data and send it to web server that is written by php.I made a form there and of course my form has a submit button but when the user press the button in the application how can i tell the form to submit the text that user choses.
我有一个 iphone 应用程序，当用户按下按钮时，我收集数据并将其发送到由 php 编写的 web 服务器。我在那里制作了一个表单，当然我的表单有一个提交按钮，但是当用户按下应用程序中的按钮时我如何告诉表单提交用户选择的文本。 here is my php code这是我的 php 代码
<?php require_once('Connections/local.php')?>
<?php
if (isset($_POST['appy_level'])){
$id=mysql_insert_id();
$appy_level=$_POST['appy_level'];
$year=$_POST['year'];
$date =date('Y');
$year=$date-$year;
$reasons = $_POST['reasons'];
$reasons = str_replace(","," ",$reasons);
if(isset($_POST['sex']))
$sex=$_POST['sex'];
$country=$_POST['country'];
$city=$_POST['city'];
$id=mysql_insert_id();
$insertSQL = "INSERT INTO user (age,wname,slid,time,sex) VALUES (".$year.",".$reasons.",".$appy_level.",CURRENT_TIMESTAMP,".$sex.")";
$insertSQL1="INSERT INTO country (c_name) VALUES (".$country.")";
$insertSQL2="INSERT INTO city (ci_name) VALUES (".$city.")";
mysql_select_db($database_local, $local);
mysql_query($insertSQL, $local) or die(mysql_error());
mysql_query($insertSQL1, $local) or die(mysql_error());
mysql_query($insertSQL2, $local) or die(mysql_error());
}
?>
<body>
<form action="" method="post" name="form1" id="form1">
<table>
<tr>
<td>Happyness level:</td>
<td>
<input type="text" name="appy_level" value="" maxlength="100" />
</td>
</tr>
<tr>
<td>Reasons:</td>
<td>
<input type="text" name="reasons" value="" maxlength="100" />
</td>
</tr>
<tr>
<td>Gender:</td>
<td>
<input type="text" name="sex" value="" maxlength="100" />
</td>
</tr>
<tr>
<td>Country:</td>
<td>
<input type="text" name="country" value="" maxlength="100" />
</td>
</tr>
<tr>
<td>City:</td>
<td>
<input type="text" name="city" value="" maxlength="100" />
</td>
</tr>
<tr>
<td>Year:</td>
<td>
<input type="text" name="year" value="" maxlength="100" />
</td>
</tr>
<tr><td> </td>
<td>
<input type="submit" value="Submit" />
</td>
</tr>
</table>
</body>
How can i submit my form without a submit button.我如何在没有提交按钮的情况下提交我的表单。 when the user presses the button ok in iphone application i want to submit his information to database.当用户在 iphone 应用程序中按下按钮确定时，我想将他的信息提交到数据库。
1 个解决方案
解决方案1
1 已采纳 2011-07-18 14:35:32
I do not see where you are connecting to your database, the connection you are trying to use is $local , here:我没有看到您连接到数据库的位置，您尝试使用的连接是$local ，这里：
mysql_query($insertSQL, $local) or die(mysql_error());
If the values you are trying to insert are strings, you need to enclose them in single quotes:如果您尝试插入的值是字符串，则需要将它们括在单引号中：
INSERT INTO tableName(col1, col2, col3, ..., colN) VALUES('val1', 'val2', 'val3', ..., 'valN')
You should wrap the string values in quotes and not forget to protect against sql injection by escaping the strings:您应该将字符串值括在引号中，并且不要忘记防止 escaping 注入 sql 字符串：
$val1 = mysql_real_escape_string($_POST['val1']);
$query = "INSERT INTO tableName(val1) VALUES('" . $val1 . "')";
mysql_query($query, $local);
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