[英]Increment IP address
In that program I want to increment IP address.在那个程序中,我想增加 IP 地址。 And I see output like that:
我看到 output 是这样的:
125.23.45.67
126.23.45.67
127.23.45.67
128.23.45.67
129.23.45.67
130.23.45.67
131.23.45.67
132.23.45.67
133.23.45.67
134.23.45.67
But I want to see output like this:但我想看到这样的 output :
124.23.45.67
124.23.45.68
124.23.45.68
124.23.45.70
124.23.45.71
124.23.45.72
124.23.45.73
124.23.45.74
124.23.45.75
124.23.45.76
Here is program code:这是程序代码:
#include <stdlib.h>
#include <stdio.h>
#include <iostream>
using namespace std;
#include "winsock2.h"
#pragma comment(lib,"wsock32.lib")
void main()
{
in_addr adr1;
in_addr adr2;
int i;
adr1.s_addr=inet_addr("124.23.45.67");
adr2.s_addr=inet_addr("as.34.34.56");
if (adr1.s_addr!=INADDR_NONE)
cout << " adr1 correct" << endl;
else
cout << " adr1 incorect " << endl;
if (adr2.s_addr!=INADDR_NONE)
cout << " adr2 correct" << endl;
else
cout << " adr2 incorect" << endl;
cout << inet_ntoa(adr1) << endl;
cout << inet_ntoa(adr2) << endl;
for (i=0;i<10;i++)
{
adr1.s_addr ++;
cout << inet_ntoa(adr1) << endl;
}
}
Big endian and little endian gets another one.大端和小端得到另一个。 Use htonl and ntohl to convert back and forth.
使用 htonl 和 ntohl 来回转换。
for (i=0;i<10;i++)
{
adr1.s_addr = htonl(ntohl(adr1.s_addr) + 1);
cout << inet_ntoa(adr1) << endl;
}
To increment an IP address you will need to break up the in_addr
object into 4 int
objects (a short int
will also do) and increment the 4th one until it hits 256, and then reset it to 1 and increment the 3rd one, etc. You shouldn't be using ++
on the in_addr
object directly.要增加 IP 地址,您需要将
in_addr
object 分解为 4 个int
对象( short int
也可以)并增加第 4 个直到达到 256,然后将其重置为 1 并增加第 3 个,等等。您不应该直接在in_addr
object 上使用++
。
EDIT: Okay, so you can properly increment it if you reverse the byte order.编辑:好的,所以如果你颠倒字节顺序,你可以适当地增加它。 I personally wouldn't do it that way.
我个人不会那样做。 Especially if all you're doing is outputting IP strings and not using them as an
in_addr
elsewhere in code.特别是如果您所做的只是输出 IP 字符串,而不是将它们用作代码中其他地方的
in_addr
。
Instead of using adr1.s_addr
:而不是使用
adr1.s_addr
:
adr1.s_addr=inet_addr("124.23.45.67");
adr2.s_addr=inet_addr("as.34.34.56");
Use this:用这个:
u_long addr1=inet_addr("124.23.45.67");
And increment addr1
, ie addr1++
the last octet gets incremented.并递增
addr1
,即addr1++
最后一个八位字节递增。
Or follow this formula:或遵循以下公式:
if IP is A.B.C.D then u_long addr = A + 256*B + 256*256*C + 256*256*256*D
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.