重音字符的正则表达式

Question

I need to build a regex (in PHP) that match if a string has at least one character different from a set provided. Here is my set:

A to Z and a to z, numbers, and áéíóúüÁÉÍÓÚÜ¡¿?:-:

So this word should not match: Sebastián This match: Sebastiàn

I reprhased the question due to the comment of varchar256. BTW, when examples differ from verbose instructions, take the example as the true intention of the author of the doc.

Answer 1

preg_match('/[^A-Za-z0-9áéíóúüÁÉÍÓÚÜ¡¿!?\-:]/', ...);

Note the ^ inside the brackets - that inverts the match, so this regex will match on any strings which contains at least one character that is NOT listed inside the brackets.

Answer 2

Use a character set pattern: preg_match('/[^\wáéíóúüÁÉÍÓÚÜ¡¿?:-:]/')

Answer 3

$string = "Sebastiàn";

$clean_string = preg_replace("/[^a-zA-ZáéíóúüÁÉÍÓÚÜ¡¿!?\\-:]*/",$string);

make sure to escape the dash in character class.