如何在 flex 3 中创建和使用弹出窗口 window？

Question

I have used a datagrid and one button in control bar. by clicking button the application goes edit state from base state. My question is how can i use popup for editing selected record of datagrid instead of changing state. please give me any example with code that describe how pop ups can be used in flex 3 application.

Answer 1

I got answer for above problem. First we have to create custom component for popup named MyPopup

And in application:

import components.popups.MyPopup;
public var pop:MyPopup;
public function Show_Pop():void
            {

             pop= PopUpManager.createPopUp(this,MyPopup,true)  as MyPopup;
             PopUpManager.centerPopUp(pop);

             }

calling function:

<mx:Button  click="Show_Pop()" id="btn1" label="show Popup"/>