如何计算与查询匹配的行数，但只返回SQL中的子集？

Question

At present, I have this code:

$result = $db->prepare("SELECT * FROM `users` WHERE MATCH (`name`, `blurb`) AGAINST (:quer IN BOOLEAN MODE) LIMIT $rpage, $max_show;");
$result->execute(array(":quer" => $query));

$count = $db->prepare("SELECT COUNT(*) FROM `users` WHERE MATCH (`name`, `blurb`) AGAINST (:quer IN BOOLEAN MODE);");
$count->execute(array(":quer" => $query));

The first query grabs a bunch of rows from the table. The second one counts the rows that match the same criteria as the first, allowing for pagination.

Can I combine these two queries into one? And would it be more efficient?

Answer 1

check into using SQL_CALC_FOUND_ROWS. You add that to your select in the first query and then just call SELECT FOUND_ROWS() after. You can read more about it here: http://dev.mysql.com/doc/refman/5.0/en/information-functions.html#function_found-rows . and yes this would be more efficient than running the search query 2 times.

Answer 2

根据mysqlperformanceblog的MySQL专家的基准测试 ， 运行两个单独的查询可能比在一个查询中组合这两个查询更快 。