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InitWithCoder,[super init]还是[super initWithCoder]?

[英]InitWithCoder, [super init] or [super initWithCoder]?

Can I ask which version I should be using, in my older apps I seem to be using "B" but when I look at a lot of examples online I am seeing a lot of versions that look like "A". 我可以问我应该使用哪个版本,在我的旧应用程序中,我似乎使用“B”但是当我在网上查看很多示例时,我看到很多版本看起来像“A”。

// A
- (id)initWithCoder:(NSCoder *)decoder {
    self=[super initWithCoder:decoder];
    if(self) {
        ...

OR 要么

// B
- (id)initWithCoder:(NSCoder *)decoder {
    self=[super init];
    if(self) {
        ...

Depends on whether the superclass conforms to the NSCoding protocol or not. 取决于超类是否符合NSCoding协议。 If it does, you must call [super initWithCoder:decoder] . 如果是,则必须调用[super initWithCoder:decoder] If it does not, you must call the superclass' designated initializer. 如果没有,则必须调用超类的指定初始化程序。

For example, if your class is a direct subclass of NSObject , you would call [super init] , NSObject 's designated initializer, since NSObject does not conform to the NSCoding protocol. 例如,如果您的类是NSObject的直接子类,那么您将调用[super init]NSObject的指定初始化程序,因为NSObject不符合NSCoding协议。

If the superclass adopts NSCoding (which is likely albeit not always the case), always call 如果超类采用NSCoding (可能并非总是如此),请始终调用

[super initWithCoder:decoder]

Otherwise call its designated initializer. 否则调用其指定的初始化程序。

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